Start learning 50% faster. Sign in now
ATQ, Let price of watch for 'M'= 100x Price for N = 120% of 100x = 120x Price for X when N sold the watch to him = 90% of 120x = 108x Price for X when M sold the watch to him = 110% of 100x = 110x ATQ, 110x – 108x = 16 x = 8 Price at which N bought that watch from M = 120x = Rs.960
20.22 × 11.99 + 140.15 = ?
What will be the approximate value of the following questions.
(79.79% of 400.23 + 7/8 of 319.77) × (√35.66 + 1/5 of 200.27) = ?
(18.22) 2.02 + (13.89) 2.12 – (44.88) 2.07 = ? – 1604.85
17.06 2 + √36.08 – (4.04/2.99) × 3.02 × 4.92 = ? × 4.99
999.99 + 99.99 + 99 = ?
What will be the approximate value of the following questions.
19.912 - (599.98 - 96.01 ÷ 3.01) ÷ 1.98 = ? + √254
The average marks of 15 candidates were reported as 84. However, it was later discovered that the marks of three candidates were ...
? = 25.08 + 11.99 × 24.07