Question
If (3/7) of 'x' is greater than
(2/11) of 'x' by 38, then determine the value of 'x'.Solution
ATQ, {(2/11) × x} + 38 = (3/7) × x Or, 38 = (3x/7) - (2x/11) Or, 38 = {(33x - 14x)/77} Or, 38 × 77 = 19x So, x = {(38 × 77)/19} = 154
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