Question
The ages of two siblings, John and Mary, are in the
ratio of 5:3. Five years ago, the sum of their ages was 38 years. What are their current ages?Solution
Let John’s current age be 5x years and Mary’s current age be 3x years. According to the problem, five years ago: John's age = 5x - 5 Mary's age = 3x - 5 The sum of their ages five years ago was 38 years: (5x - 5) + (3x - 5) = 38 Simplifying the equation: 5x - 5 + 3x - 5 = 38 8x - 10 = 38 8x = 48 x = 6 Now, substituting x back to find their ages: John's age = 5x = 5(6) = 30 years Mary's age = 3x = 3(6) = 18 years
Which of the following other boxes are placed in a stack where H is placed?Â
How many floors are there in between the floor of the one who likes Shubham Gill and the one who lives at floor 8th?
How many rows are vacant?
Seven persons S, T, U, V, W, X and Y live on different floor of a seven-storey building. The bottommost floor is numbered as 1 and the topmost floor is...
Who among the following live immediate below C?
Who among the following is the second youngest?
Four of the following five are alike in a certain way and form a group. Which of the following does not belong to the group?
Who among the following celebrated his birthday immediately before H?
How many students appear for RBI exam?
If all the persons are arranged in alphabetical order from bottom to top, then how many persons remain unchanged in their positions?
