Question
Two pipes A and B can fill a tank in 15 hours and 20
hours, respectively. Another pipe C can empty the tank in 30 hours. If all three pipes are opened together, how long will it take to fill the tank?Solution
Work done by A in 1 hour = 1/15. Work done by B in 1 hour = 1/20. Work done by C (emptying) in 1 hour = β1/30. Net work done in 1 hour = 1/15 + 1/20 β 1/30. LCM of 15, 20, and 30 is 60. Net work done in 1 hour = (4 + 3 β 2)/60 = 5/60 = 1/12. Time taken to fill the tank = 12 hours. Thus, the correct answer is 12 hours . Ans. a
(350/?) = 23 + 33
(630 Γ· 35) Γ 2 + 144 = ? Γ 2
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
236.23-653.23+696.23=?
72 Γ 2 = ? + 104 β 14
36895 - 4256 - 2233 = ?Β
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)? = 15% of 2400 + 140% of 4200 β 12 3Β
β121 + β961β β289 =?2
