Question
I. 3x² - 15x + 18 = 0 II. 2y² - 8y + 6 =
0 In each of the following questions, two equations are given. You have to solve both the equations to find the relation between x and y.Solution
From equation 1: 3x² - 15x + 18 = 0 Dividing by 3: x² - 5x + 6 = 0 Factorizing: (x - 3)(x - 2) = 0 So, x = 3 or x = 2. From equation 2: 2y² - 8y + 6 = 0 Dividing by 2: y² - 4y + 3 = 0 Factorizing: (y - 3)(y - 1) = 0 So, y = 3 or y = 1. Comparing x and y: • If x = 3 and y = 3, x = y. • If x = 2 and y = 3, x < y. • If x = 2 and y = 1, x > y. Thus, x can be both greater than or less than y. Answer: C
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