Question
'Ankit' can complete a certain
task by himself in 20 days. 'Bheema' is 40% more efficient than 'Ankit'. If 'Ankit' works alone for 6 days and then leaves, how long will it take 'Bheema' to finish the remaining work on his own?Solution
ATQ, Let the efficiency of 'Ankit' be 'a' units/day. So, efficiency of 'Bheema' = a × 1.40 = '1.4a' units/day So, total work = 20 × a = '20a' units Work done by 'Ankit' in 6 days = 6 × a = '6a' units So, time taken by 'Bheema' to finish the remaining work = (20a - 6a) ÷ 1.4a = (14a/1.4) = 10 days
What value should come in place of (?) in the given expression.
450 ÷ 9 + 75% of 160 − 64 ÷ 4 = ?
2/5 of 3/4 of 7/9 of 14400 = ?
7/3 of 4/5 of 15/56 of ? = 83
[564 + 32 of 18 × 9 ÷ 12 + 162 ] ÷ 4 = ?
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
45% of 360 - 160 + ? = √324
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
18 × 15 + 86 – 58 =? + 38
√(24²+285-8²-172) = ?²
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