Question
'Ankit' can complete a certain
task by himself in 20 days. 'Bheema' is 40% more efficient than 'Ankit'. If 'Ankit' works alone for 6 days and then leaves, how long will it take 'Bheema' to finish the remaining work on his own?Solution
ATQ, Let the efficiency of 'Ankit' be 'a' units/day. So, efficiency of 'Bheema' = a × 1.40 = '1.4a' units/day So, total work = 20 × a = '20a' units Work done by 'Ankit' in 6 days = 6 × a = '6a' units So, time taken by 'Bheema' to finish the remaining work = (20a - 6a) ÷ 1.4a = (14a/1.4) = 10 days
the following question the relationship between different elements is given in the statements followed by two conclusions given below. Decide which of...
Statements: D = P > Q = X ≤ Y = M; J = X; K > Q
Conclusion: I. M > K II. M ≤ K
Statements:Â
A $ B % D % CÂ
Conclusions:Â
I. B © CÂ
II. A * DÂ
III. C % A
Statements: A = C > G > H = B > O; E < P = R > B
Conclusions:
I). Â E > H
II).  H ≤ E
...In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is/are definitely true and th...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is/are definitely true and th...
Statements: M ≥ G > K = Y; A ≥ Z ≥ E > M = I
Conclusions:
I. A ≥ I
II. K < E
III. I > G
Statements: R ≥ S = T; R < U < V; W > X > V
Conclusion:
I. U > T
II. T < V
Statements: R > N > Z < O = I ≥ T < W < S ≤ L
Conclusion
I: L > Z
II: O > T
Statement: E < N < Q = W = F ≥ U > A
Conclusion:
I. Q > A
II. E > F
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