Question
A man allocates 12%, 18%, and 20% of his salary to his
three children, P, Q, and R, respectively. The children spend 50%, 60%, and 56% of their received amounts. The difference between the total money left with the children and the man is Rs. 3360. What is the man's salary?Solution
Let the salary of man = 100x He gives 12x, 18x and 20x to children Savings of man = 100x – (12x+18x+20x) = 50x Savings of P = 50% of 12x = 6x Savings of Q = 40% of 18x = 7.2x Savings of R = 44% of 20x = 8.8x Total savings of P, Q and R = 6x+7.2x+8.8x = 22x Difference = 3360 50x-22x = 3360 28x = 3360 X = 120 Total salary of man = 100x = 12,000
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
