Question
The value of cosĀ² 10Ā° + cosĀ² 20Ā° + cosĀ² 30Ā° +
ā¦ā¦. + cosĀ² 90Ā° isSolution
ATQ, We know cos(90Ā° - A) = sin A cosĀ² 10 + cosĀ² 20 + cosĀ² 30Ā° +ā¦ā¦. + cosĀ² 90Ā° = cosĀ² 1 + cosĀ² 20 + cosĀ² 30Ā° + cosĀ² 40Ā° + sinĀ² 40+ sinĀ² 30Ā° + sinĀ² 20 + sinĀ² 10+ cosĀ² 90 = (sınĀ² 10Ā° + cos2 10) + (sinĀ² 20 + cosĀ² 20) + (sinĀ² 30Ā° + cosĀ² 30) + (sinĀ² 40+ cosĀ² 40Ā°) + cosĀ² 90 = 1+1+1+1+0 = 4
(500 Ć 6 Ć· 10) - (ā256 + 8) = ?
22% of 400 +Ā ā ? = 34% of 800 - 25% of 400
(2/5)(32% of 4500 ā 440) = ? Ć 8
1550 Ć· 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)Ā Ā Ā Ā Ā Ā
What will come in the place of question mark (?) in the given expression?
96 Ć· (9 - 6.6) + 17.5 X 6 = ? Ć· 8Ā
13 X ? = 85 X 4 + ā81 + 2
45% of 360 - 160 + ? = ā324
((67)32 × (67)-18 / ? = (67)āø
4567.89 - 567.89 - 678.89 = ?
82.3 Ć 644.7 Ć 723.4 Ć 815.85 = 72?
