Question
A man invested certain sum at simple interest of r% p.a.
such that it amounts to 126% of itself in 10 years. Find the interest earned when Rs. 12000 is invested at simple interest of r% p.a. for 3 years.Solution
Let the sum invested be Rs. ‘P’ Therefore, interest earned in 10 years = 1.26P – P = Rs. 0.26P ATQ; 0.26P = (P × r × 10) ÷ 100 Or, r = 26 ÷ 10 Or, r = 2.6 So, required interest earned = (12000 × 2.6 × 3) ÷ 100 = Rs. 936
799.99 + 1500.12 ÷ 29.98 × 50.01 = ? × 24.96
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