Question
A man invested certain sum at simple interest of r% p.a.
such that it amounts to 126% of itself in 10 years. Find the interest earned when Rs. 12000 is invested at simple interest of r% p.a. for 3 years.Solution
Let the sum invested be Rs. ‘P’ Therefore, interest earned in 10 years = 1.26P – P = Rs. 0.26P ATQ; 0.26P = (P × r × 10) ÷ 100 Or, r = 26 ÷ 10 Or, r = 2.6 So, required interest earned = (12000 × 2.6 × 3) ÷ 100 = Rs. 936
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the question...
3, 49, 191, 477, ?, 1673
What will be the next number in the series?
2,5,11,23,47,?
38    40    83    254    ?     5126
24 47 137 ? 2679 16049
...10 625 50 125 250 25 ?
...[(288)2 ÷ 96 × ?] ÷ 44 = 432
1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...
3, 4, 10, 33, 136, ?, 4116
77 ? 190 257 331 412
...
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