Question
A man invested certain sum at simple interest of r% p.a.
such that it amounts to 126% of itself in 10 years. Find the interest earned when Rs. 12000 is invested at simple interest of r% p.a. for 3 years.Solution
Let the sum invested be Rs. βPβ Therefore, interest earned in 10 years = 1.26P β P = Rs. 0.26P ATQ; 0.26P = (P Γ r Γ 10) Γ· 100 Or, r = 26 Γ· 10 Or, r = 2.6 So, required interest earned = (12000 Γ 2.6 Γ 3) Γ· 100 = Rs. 936
β323.89 Β Γ (3.20) Γ· 9.02 =?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
23.98% of 624.99 = 19.98% of ? + 14.98% of 639.99
Direction: Please solve the following expression and choose the closest option
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
12, 16, ?, 36, 52, 72Β
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(6859.01)1/3 Β Γ 10.11 Γ 14.47 Γ· 20.32 = ?Β + 45.022
33.33% of 809.891 + 66.66% of 212.91 = ?