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Start learning 50% faster. Sign in nowLet the sum invested be Rs. ‘P’ Therefore, interest earned in 10 years = 1.26P – P = Rs. 0.26P ATQ; 0.26P = (P × r × 10) ÷ 100 Or, r = 26 ÷ 10 Or, r = 2.6 So, required interest earned = (12000 × 2.6 × 3) ÷ 100 = Rs. 936
(512) (2/3) × √64 ÷ (512) (1/3) = (64) (?/2) ÷ (2)6
9 × 4 ? ÷ 16 = 144
(6.013 – 20.04) = ? + 9.98% of 5399.98
What will come in the place of question mark (?) in the given expression?
(20% of 820 – 56 + 11 × 8) 1/2 = ? – 62
Find the value of ‘a’ in the following expression:
12 × a × 24 ÷ 8 + 72 – 46 = 170
72 + 122 - 25% of 600 = ?
192.251 + 326.233 + 125.021 + 19.273 = ?
55.55% of 30000 – 1111 = ? × 1111
(23.95)2 – (25.006)2 + (8.0099)2 – (7.07)2 = ? - (14.990)2