Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between x and y and choose the correct option. I. (x + 2)² = 15x – 26 II. (y – 6)² = 6 – ySolution
ATQ,
(x + 2) ² = 15x – 26
x² + 4x + 4 = 15x – 26
x² – 11x + 30 = 0
x² – 5x – 6x + 30 = 0
x(x – 5) – 6(x – 5) = 0
(x – 5)(x – 6) = 0
x = 5, 6
From II:
(y – 6) ² = 6 – y
y² – 12y + 36 = 6 – y
y² – 11y + 30 = 0
y² – 5y – 6y + 30 = 0
y(y – 5) – 6(y – 5) = 0
(y – 5)(y – 6) = 0
y = 5, 6
So, the relationship cannot be established.
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