Question
I. p2 - 53p + 672 = 0 II.
q2 - 27q + 126 = 0 The following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give the answer.Solution
ATQ, p2 - 53p + 672 = 0 p2 - 32p – 21p + 672 = 0 p = 32, 21 q2 - 27q + 126 = 0 q2 - 21q – 6q + 126 = 0 q = 21, 6 Hence, p ≥ q
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