Question
One of the roots of the equation p2Â - (y+3)p
+ 6y = 0 is cube of 2. What will be the difference of other root and 'y'.Solution
ATQ, p2 – (y+3)p + 6y = 0 one of the roots is 23 = 8 So, let other roots is 'a' So, a + 8 = (y+3) and 8 × a = 6y So, a + 8 = 8a/6 + 3 or, 6a + 48 = 8a +18 or, 2a = 30, a = 15 So, other root is 15 and value of 'y' = 15 + 8 - 3 = 20 So, difference is= 20 - 15 = 5
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