Question
The perimeter of a rectangle is 120% more than perimeter of a square of side 10
cm. If the length of rectangle is 250% more than side of square then find the difference between the area of square and the area of rectangle.
Solution
Perimeter of the square = 4 x 10 = 40 cm Perimeter of the rectangle = 40 x (220/100) = 88 cm Length of the rectangle = 10 x (350/100) = 35 cm Let the breadth of the rectangle be b cm. => 2 x (35 + b) = 88 => b = 44 β 35 => b = 9 cm Required difference = (9 x 35) - (10 x 10) = 215
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