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    Question

    I. 12 x ² -

    3 x – 15 = 0 II. 2 y² + 12 y + 10 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x ≤ y Correct Answer Incorrect Answer
    C If x ≥ y Correct Answer Incorrect Answer
    D If x < y Correct Answer Incorrect Answer
    E If x = y or relationship between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. 12 x ² - 3 x – 15 = 0 (4 x - 5) (3 x + 3) = 0 x = `(5)/(4)` [if gte msEquation 12]> 5 4 [if !msEquation]--> [endif]--> , - 1 II. 2 y² + 12 y + 10 = 0 (2 y + 2) ( [if gte msEquation 12]>y [if !msEquation]--> y+ 5) = 0 [if gte msEquation 12]>y [if !msEquation]--> [endif]-->y = -5, -1 Hence, If [if gte msEquation 12]>x [if !msEquation]--> [endif]-->x ≥ y [if gte msEquation 12]>y [if !msEquation]--> [endif]-->

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