Question
I. 49y2 + 35y + 6 = 0 II.
12x2 + 17 x + 6 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 49y2 + 35y + 6 = 0 49y2 + 21y + 14 y + 6 = 0 7 y (7 y + 3) + 2 (7 y + 3) = 0 (7 y + 2) (7 y + 3) = 0 y = -2/7, -3/7 II. 12x2 + 17 x + 6 = 0 12x2 + 8 x + 9 x + 6 = 0 4 x (3 x + 2) + 3 (3 x + 2) = 0 (4 x + 3) (3 x + 2) = 0 x = -3/4, -2/3 Hence, x < y
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