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    Question

    I. 49y2 + 35y + 6 = 0 II.

    12x2 + 17 x + 6 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x тЙе y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x тЙд y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 49y2 + 35y + 6 = 0 49y2 + 21y + 14 y + 6 = 0 7 y (7 y + 3) + 2 (7 y + 3) = 0 (7 y + 2) (7 y + 3) = 0 y = -2/7, -3/7 II. 12x2 + 17 x + 6 = 0 12x2 + 8 x + 9 x + 6 = 0 4 x (3 x + 2) + 3 (3 x + 2) = 0 (4 x + 3) (3 x + 2) = 0 x = -3/4, -2/3 Hence, x < y

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