Question
I. 49y2 + 35y + 6 = 0 II.
12x2 + 17 x + 6 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 49y2 + 35y + 6 = 0 49y2 + 21y + 14 y + 6 = 0 7 y (7 y + 3) + 2 (7 y + 3) = 0 (7 y + 2) (7 y + 3) = 0 y = -2/7, -3/7 II. 12x2 + 17 x + 6 = 0 12x2 + 8 x + 9 x + 6 = 0 4 x (3 x + 2) + 3 (3 x + 2) = 0 (4 x + 3) (3 x + 2) = 0 x = -3/4, -2/3 Hence, x < y
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 32x + 252 = 0
Equation 2: y² - 30y + 221 = 0
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
If the roots of the quadratic equation 5x² + 4x + 6 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 5x + 6 = 0
Equation 2: y² - 7y + 12 = 0
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 88x + 100 = 0
Equation 2: 17y² - 79y + 90...
I. 8x² - 78x + 169 = 0
II. 20y² - 117y + 169 = 0
l. x2 - 16x + 64 = 0
II. y2Â = 64
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
Solve both equations I & II and form a new equation III in variable ‘r’ (reduce to lowest possible factor) using roots of equation I and II as per ...
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