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    Question

    I. 2x2 - 15x + 25 = 0 II.

    3y2 - 10y + 8 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 2x2 - 15x + 25 = 0 2x2 - 5x - 10x + 25 = 0 x (2 x – 5) – 5(2 x – 5) = 0 (x – 5)(2 x – 5) = 0 x = 5, 5/2 II. 3y2 - 10y + 8 = 0 3y2 - 6 y - 4y + 8 = 0 3 y (y - 2) – 4(y – 2) = 0 (3 y – 4) (y – 2) = 0 y = 2, 4/3 Hence, x>y

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