Question
Ravi purchases two wrist watches for a total of Rs. 600. He sells one watch at 4/5 of its cost price and the other at 6/5 of its cost price, and makes an overall profit of Rs. 60. What is the cost price of the cheaper watch?
Solution
Let the cost price of one watch = Rs. x Then, cost price of the other watch = Rs. (600 – x) According to the question, x × 4/5 + (600 – x) × 6/5 = 600 + 60 4x/5 + 3600/5 – 6x/5 = 660 4x/5 – 6x/5 = 660 – 720 –2x/5 = –60 x = (–60 × 5)/(–2) x = 150 Cost price of first watch = Rs. 150 Cost price of second watch = 600 – 150 = Rs. 450 Hence, Between ₹150 and ₹450, the cheaper watch is ₹150 .
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