Question
A dishonest seller, at the time of selling and
purchasing uses weight 10% less and 20% more per kg respectively. Find the approx. percent profit earned by him if he sells his goods at cost price.Solution
C.P of 1200 gm = Rs 1000 CP of 900 gm = Rs 750 SP of 900 gm = Rs 1000 Â % profit =Â `250/750xx` 100Â = 33.33% approx.
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
I). p2 - 20p + 51 = 0,
II). 2q2 - 7q + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 5x + 6 = 0
Equation 2: y² - 7y + 12 = 0
I. 2x2 + 3x - 9 = 0
II. 3y2 - y - 10 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 88x + 100 = 0
Equation 2: 17y² - 79y + 90...
I. 2y2Â + 31y + 99 = 0
II. 4x2 + 8x – 45 = 0
I. 4x2 – 53x – 105 = 0
II. 3y2 – 25y + 48 = 0
I. (y – 5)2 – 9 = 0
II. x2 – 3x + 2 = 0