Question
A man bought two properties. The cost of the first
property is 60% of the cost of the second property. He sold the first property at a profit of 25% and the second property at a loss of 20%. The total selling price of both properties is Rs 46,500. What is the cost price of the first property?Solution
Let the cost of the second property be 10x Then, the cost of the first property = 6x Selling Price of the first property = 125% of 6x = 7.5x Selling Price of the second property = 80% of 10x = 8x Total Selling Price = 8x+7.5x = 15.5x 15.5x = 46,500 x = 3000 cost price of first property = 6x = 18,000
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