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Let the CP of the article be 100a. Now, SP for 1st case = 100a - 100a × 10(1/2) % = 89.5a SP for 2nd case = 100a + 100a × 11(3/5) % = 111.6a According to the question, 111.6a - 89.5a = 375.70 22.1a = 375.70 a = 375.70/22.1 a = 17 So, cost price = 100 × 17 Rs. 1700 ∴ The cost price (in Rs.) of the article is 1700. Second method- Given – loss% = 10(1/2) and profit% 11(3/5) Increased selling price = 375.70 Let cost price =100 ATQ- 10(1/2) +11(3/5) = 375.70 21/2 + 58/5 = 375.70 (105 + 116) /10 =375.70 1 =3757/221 = 17 Then CP = 100×17 = 1700 Rs
154 × 7 + 480 × 5 = ?% of 6956
(3/7) x 868 + 25% of 240 = (? + 65)
53 – 8 = ? + 126
√289 + √49 + 121 =?
18/2 of 3/9 of 2/6 of 69690 = ?
30% of 60% of 1800 + 13 × 14 = (? ÷ 75) × 5
6 0 - 20 [8 + 12 {8-8 (20-12)+20}-40] ÷ 16 =?
The value of 11 × 11 + 11 ÷ 11 – 11 × 11 + 11 + 11 × 11 – 11 – 11 × 11 is: