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P(x) = 5x 3  + 4x 2  – 10x + 1
G(x) = 2x – 4
According to remainder theorem, Put G(x) = 0
i.e. 2x – 4 = 0
Or, 2x = 4
Or, ‘x’ = 2
Required remainder = P(2)
= (5 × 2 3 ) + (4 × 2 2 ) – (10 × 2) + 1 = (5 × 8) + (4 × 4) – 20 + 1
= 40 + 16 – 19 = 37
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