Question
Anil sold 12 cameras at a loss of 10%. If he had sold
all the cameras for Rs. 1440 more, his overall profit would have been 20%. What is the cost price of 8 cameras?Solution
 Let the cost price of each camera be Rs. c.  Initial selling price of all cameras = 0.9 × 12 × c = Rs. 10.8c  According to the question, 10.8c + 1440 = 1.2 × 12c Or, 14.4c - 10.8c = 1440 Or, 3.6c = 1440 Or, c = 400 Therefore, the cost price of 8 cameras = 8 × c = Rs. 3200
390/? = √256 + 3.5
600 ÷ 8 + 12 % of 250 + ? * 14 = 50 * √49
? × 5.5 = √1225 + 40% of 30% of 37.5% of 5000 – 63
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
35% of 500 × 22% of ? = 847
144% of 200 + 11% of 900 + 10% of 20 =?
√0.49 + √6.25 + √1.44 + √1.21 =? % of 125
4.7 × 3.5 + 4.2 × 4.5 = 22.5 × 3.5 - ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82.3 × 644.7 × 723.4 × 815.85 = 72?