Question
Two balls are drawn successively without replacement
from a bag containing 4 red balls, 5 blue balls, and 6 green balls. What is the probability that one ball is red and the other is blue?Solution
Total balls = 4 + 5 + 6 = 15 Probability of one red and one blue can happen in 2 ways: Red then Blue = 4/15 x 5/14 Blue then Red = 5/15 x 4/14 Total probability = (4/15 x 5/14) + (5/15 x 4/14) = 20/210 + 20/210 = 40/210 = 4/21 So, probability = 4/21
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