Question
A bag contains 7 blue balls, 28 red balls, and 10 green
balls. One ball is drawn at random. Find the probability that the ball drawn is either blue or green.Solution
ATQ, Total number of balls in the bag =7+ 28 + 10 = 45 Probability of selecting 1 blue ball out of all the balls, P(E1) = (7/45) Probability of selecting 1 green ball out of all the balls, P(E2) = (10/45) The probability of drawing either blue ball or green ball = , P(E1) + P(E2) = (7/45) + (10/45) = (17/45)Â
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