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    Question

    A bag contains 7 blue balls, 28 red balls, and 10 green

    balls. One ball is drawn at random. Find the probability that the ball drawn is either blue or green.
    A 17/45 Correct Answer Incorrect Answer
    B 23/45 Correct Answer Incorrect Answer
    C 16/25 Correct Answer Incorrect Answer
    D 11/18 Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Total number of balls in the bag =7+ 28 + 10 = 45 Probability of selecting 1 blue ball out of all the balls, P(E1) = (7/45) Probability of selecting 1 green ball out of all the balls, P(E2) = (10/45) The probability of drawing either blue ball or green ball = , P(E1) + P(E2) = (7/45) + (10/45) = (17/45) 

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