Question
A bag contains 5 red balls, 4 blue balls and 3 green
balls. If one ball is drawn at random, what is the probability that the ball drawn is neither red nor green?Solution
ATQ, Total number of balls = 5 + 4 + 3 = 12 "Neither red nor green" means the ball must be blue. Number of blue balls = 4 Required probability = Number of favorable outcomes / Total number of outcomes = 4/12 = 1/3
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