Question
A container holds 15 orange, 9 purple, and 6 gray balls.
If 2 balls are picked at random without replacement, find the probability that the first ball is orange and the second ball is either purple or gray.Solution
ATQ, Total number of balls = 15 + 9 + 6 = 30 Case I: First ball is orange and the second ball is purple. Probability = (15/30) × (9/29) = 45/145 = 9/29 Case II: First ball is orange and the second ball is gray. Probability = (15/30) × (6/29) = 30/145 = 6/29 Required probability = (9/29) + (6/29) = 15/29
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