Question
Bag A contains 4 red balls and 6 blue balls, whereas
bag B contains 5 red balls and 3 blue balls. One ball is drawn at random from A and transferred into B. Two balls are now drawn at random from B. Find the probability that both balls are of the same colour.Solution
Required probability
= (4/10) X (6/9) X (5/8) + (4/10) X (3/9) X (2/8) + (6/10) X (5/9) X (4/8) + (6/10) X (4/9) X (3/8) = (1/6) + (1/30) + (1/6) + (1/10) = (5/30) + (1/30) + (5/30) + (3/30) = (14/30) = (7/15)
7/11 × 1034 + 1(4/7) × 2401 = 1230 +?
140% of 9/8 of ? = 108% of 2800
4.56 + 56.4 + 64.5 = ? + 10.46
- What will come in the place of question mark (?) in the given expression?
?² = 28% of 35% of 4500 12.5% of (100 + ?) = 40
What will come in the place of question mark (?) in the given expression?
? = 12.5% of 25% of 20% of 1280 + 1248
(? + 180 + 13 × 6) ÷ 20 + 3.5 × 512 (1/3) = 82
Solve for the ?
What will come in the place of question mark (?) in the given expression?
(437 + ? - 167) x 2.5 = 875(22% of 1500 + 15% of 2200) = ? x 11