Question
The probability that Leah will be accepted into program
P is 60% and into program Q is 40%. Leah prefers program 'P' first, then 'Q', and finally 'R'. Assuming Leah gets into program 'R', what is the probability she will attend 'R'?Solution
ATQ, Leah will attend program 'R' only if she fails to get into program 'P' and program 'Q'. So, probability that she doesn't get into program 'P' = (1 - 0.6) = 0.4 And probability that she doesn't get into program 'Q' = (1 - 0.4) = 0.6 So, required probability = 0.4 × 0.6 = 0.24
More Probability Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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