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    Question

    A bag contains 12 blue balls, 18 red balls, and 20 green

    balls. One ball is drawn at random. Find the probability that the ball drawn is either blue or green.
    A 12/17 Correct Answer Incorrect Answer
    B 23/45 Correct Answer Incorrect Answer
    C 16/25 Correct Answer Incorrect Answer
    D 11/18 Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Total number of balls in the bag =12+ 18 + 20 = 50 Probability of selecting 1 blue ball out of all the balls, P(E1) = (12/50) Probability of selecting 1 green ball out of all the balls, P(E2) = (20/50) The probability of drawing either blue ball or green ball = , P(E1) + P(E2) = (12/50) + (20/50) = (32/50) = 16/25

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