Question
A bag has 4 red, 3 blue, and 3 green balls. Two are
drawn without replacement. Find probability that both are of different colors.Solution
ATQ,
Total = C(10,2) = 45. Same color = C(4,2) + C(3,2) + C(3,2) = 6+3+3 = 12. Different = 45 – 12 = 33. P = 33/45 = 11/15.
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