Question
A bag has 4 red, 3 blue, and 3 green balls. Two are
drawn without replacement. Find probability that both are of different colors.Solution
ATQ,
Total = C(10,2) = 45. Same color = C(4,2) + C(3,2) + C(3,2) = 6+3+3 = 12. Different = 45 – 12 = 33. P = 33/45 = 11/15.
For given pair of equations, how many solutions are possible?
3x + 4y = 15 and 6x + 8y = 10
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
For given pair of equations, how many solutions are possible?
4x + 6y = 16 and 8x + 12y = 32
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.
The ratio of roots of an equation
ax²+bx+b = 0 is p : q
Then find, √p/√q + √q/√p + √p/√q ?
I. p2 – 5p + 6 = 0                 Â
II. 36q2 = 81
...I. p² - 365 = 364
II. q - √ 529 = √ 169
For given pair of equations, how many solutions are possible?
7x − 3y = 20 and 14x − 5y = 40
If x - √3 y = 8 Find the slope in angle?
If 2x + 3y = 27 and 3x - y = 13, find (x + y).
