Question
A box contains 6 red balls, 4 blue balls and 2 yellow
balls. Two balls are picked at random. What is the probability that both balls are of the same color?Solution
ATQ,
Required probability = (6/12) × (5/11) + (4/12) × (3/11) + (2/12) × (1/11) = (30/132) + (12/132) + (2/132) = 44/132 = 4/12 = 1/3
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