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Three persons
i.e. ‘X’, ‘Y’ and ‘Z’, are given the same puzzle to solve. The probability that ‘X’, ‘Y’ and ‘Z’ will solve the puzzle is (4/7), (2/5) and (1/2), respectively. Find the probability that exactly one of them will not solve the puzzle.

A 17/35

B 11/21

C 13/35

D 2/5

E None of these

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