Question
A 6-digit number is formed using the digits 1, 2, 3, 4, 5 and 6. If each digit can be used only once, then find the probability that the number formed will be divisible by 5.
Solution
Total numbers formed = 6! = 720
Since the number is divisible by 5, therefore, at unit place only 5 can come and remaining digits can be arranged in 5! = 120 ways
Total such numbers formed = 120 × 1 = 120
Required probability = 120/720 = 1/6
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