Question
A bag has 6 red balls, 6 blue balls and 8 green balls. Two
balls are picked randomly. What is the probability that at least one of them is green?Solution
Total balls = 6 + 6 + 8 = 20
Non-green balls = 6 + 6 = 12
Required probability = 1 - (12/20) × (11/19)
= 1 - (132/380)
= 1 - (33/95)
= 62/95
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