Question
 A box contains 12 yellow marbles, ‘x’ blue marbles
and 12 white marbles. A box contains 5 yellow marbles, 2 blue marbles and 3 white marbles. The probability of drawing a blue marble at random from the box is 1/7. If (x/2) blue marbles from the box are transferred to the bag, then find the probability of drawing a blue marble and a white marble from the box.Solution
According to the question, x/ (12+ x + 12) = 1/7 => 6x = 24 => x = 4 Therefore, number of blue marbles transferred to bag = x/2 = 2 Total number of blue marbles in the box after the transfer = 2 + 2 = 4 Total number of marbles in the bag after the transfer = 5 + 2 + 3 + 2 = 12 Required probability = (4C1 × 3C1)/12C2 = 2/11
5/13 × 104 + 1(2/9) × 198 = 133 + ?
What will come in the place of question mark (?) in the given expression?
(24 2 – 16 2 ) + 75% of 40% of 480 = ?
5 + 2 × 3 ÷ (3 × 2) ÷ 4
Find the Value of √(-√3+√(3+8√(7+4√3)))?Â
- What will come in the place of question mark (?) in the given expression?
35% of 400 - 20% of 300 = (? - 30) X 2 15848 ÷ 4 – 793 × 6 + 3628 = 3 × ?
? = (22% of 25% of 60% of 3000) + 21
What will come in place of the question mark (?) in the following expression?
(320 ÷ 8 + 22) × 4 = 60 + 40% of ?
70 % of 640 + 75 % of 360 - 19 × 12 = ?
24 × ?2 – 11 × 4 = 1900
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