Question
A bag has 5 red, 4 blue, 3 green balls. Two balls are
drawn without replacement. Find probability that both are of the same color.Solution
ATQ, Total ways = C(12,2) = 66 Favourable = C(5,2)+C(4,2)+C(3,2) = 10+6+3 = 19 Probability = 19/66 Answer: 19/66
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