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    Question

    A game consists of tossing three coins once and then

    rolling two dice. Find the probability of getting no heads in the coin toss and a sum equal to 4 on the dice.
    A 1/96 Correct Answer Incorrect Answer
    B 1/64 Correct Answer Incorrect Answer
    C 1/48 Correct Answer Incorrect Answer
    D 3/64 Correct Answer Incorrect Answer
    E 1/36 Correct Answer Incorrect Answer

    Solution

    For tossing 3 coins: Total number of possible outcomes = 23 = 8 Number of favourable outcomes = 1 (TTT) So, probability of getting no heads while tossing three coins = (1/8) For rolling 2 dice: Total number of possible outcomes = 6 ├Ч 6 = 36 Number of favourable outcomes = 3 [(1,3), (2,2), (3,1)] So, Probability of getting a sum equal to 4 while rolling 2 dice = (3/36) = (1/12) Required probability = (1/8) ├Ч (1/12) = 1/96

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