Question
A game consists of tossing three coins once and then
rolling two dice. Find the probability of getting no heads in the coin toss and a sum equal to 4 on the dice.Solution
For tossing 3 coins: Total number of possible outcomes = 23 = 8 Number of favourable outcomes = 1 (TTT) So, probability of getting no heads while tossing three coins = (1/8) For rolling 2 dice: Total number of possible outcomes = 6 × 6 = 36 Number of favourable outcomes = 3 [(1,3), (2,2), (3,1)] So, Probability of getting a sum equal to 4 while rolling 2 dice = (3/36) = (1/12) Required probability = (1/8) × (1/12) = 1/96
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