Question
Two numbers are selected at random without replacement
from the first 12 natural numbers. Find the probability that both numbers are multiples of 3.Solution
Multiples of 3 in 1 to 12 = 4
Required probability = ( 4 C 2 ) / ( 12 C 2 ) = 6 / 66 = 1/11
More Probability Questions
Find the simplified of the following expression:
Simplify the following expression:
416 ÷ 8 + 132 – 25% of 420 = ?
9 × 4 ? ÷ 16 = 144
42 + 52% of 300 - ?% of 200 = 88
What value should come in place of (?) question mark in the given expression.
17 × 15 − 96 ÷ 8 + 6² = ?
19 × ? = 361 ÷ 19
Simplify the following expressions and choose the correct option.
(3/7) of {350 − [42 ÷ (3/2)]} = ?
15% of ? = 30% of 320 + 17 ×√676 – 63.5 × 8
390/? = √256 + 3.5
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