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      Question

      Two numbers are selected at random without replacement

      from the first 12 natural numbers. Find the probability that both numbers are multiples of 3.
      A 1/10 Correct Answer Incorrect Answer
      B 2/11 Correct Answer Incorrect Answer
      C 1/11 Correct Answer Incorrect Answer
      D 3/11 Correct Answer Incorrect Answer
      E 2/15 Correct Answer Incorrect Answer

      Solution

      Multiples of 3 in 1 to 12 = 4
      Required probability = ( 4 C 2 ) / ( 12 C 2 ) = 6 / 66 = 1/11

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