Question
Two people are selected randomly without replacement from a
team of 10 players, out of which 6 are right-handeFind the probability that both selected players are right-handeSolution
Total players = 10
Right-handed players = 6
Required probability = ( 6 C 2 ) / ( 10 C 2 ) = 15 / 45 = 1/3
More Probability Questions
20.05% of 220.05 – 15.15% of 99.99 × 2.02 = ?
535 + ? × 27 - 22 × 20 = 230Â
15 * 12 + 35% of 80 + 70% of 130 = ?
What will come in the place of question mark (?) in the given expression?
30% of 50% of 1200 = 18/11 × ?
? = (√784 - √361) + 102 - 3√512
13% of 200 + 56 ÷ 4 = 8% of ?Â
290 × 15 ÷ 5 + 34 + 50 = ?Â
(62 - 52 ) % of 800 = 22 X √?
What will come in the place of question mark (?) in the given expression?
(352 - ?) ÷ 8 = 2.5 X 40 - 444 ÷ 6
What will come in the place of question mark (?) in the given expression?
(28/14) of 56 + ? = 920 ÷ 5
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