Question
Karan has a 65% chance of being admitted to school L and
a 55% chance at school M. His preferences are 'L', then 'M', and lastly 'N'. Assuming Karan gets into school 'N', what is the probability that he will attend 'N'?Solution
ATQ, Karan will attend school 'N' only if he isn't accepted to school 'L' or 'M'. So, probability that he doesn't get into School 'L' = (1 - 0.65) = 0.35 And probability that he doesn't get into school 'M' = (1 - 0.55) = 0.45 So, required probability = 0.35 × 0.45 = 0.1575
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Statements:
A = B ≤ Y < Z; P ≤ I < A; M ≤ Y < N
Conclusions:
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II). Â P < Y
III). Â N > A
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