Question
'M' invested ₹19,200 at an annual compound interest
rate of 10%, compounded yearly. After 'a' years, the total amount he received was ₹23,232. If 'Q' invested ₹48,000 at an annual compound interest rate of 15%, also compounded yearly for the same duration ('a' years), what would be the total amount received by 'Q'?Solution
We know that, A = P (1 + rate/100)t Or, 23232 = 19200 X (110/100) a Or, (23232/19200) = (11/10) a Or, (121/100) = (11/10) a Or, (11/10) 2 = (11/10) a So, 'a' = 2 Therefore, interest received by 'Q' = 48,000 x (1.15) 2 - 48,000 = 63,480 - 48,000 = Rs. 15,480
√? = 120 - 102 + ∛125
350% of (450 / 1.5) = ?% of 4200
The value of (43-3× (4×6+12/6 ×6-4×5) +4)?
? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
What value should come in place of (?) question mark.
(5/9 of 396) − (35% of 320) + 7.2 = ?
What will come in the place of question mark (?) in the given expression?
[{(24) 2 ÷ (6) 2 } ÷ 8]4 = ? ÷ 5
The value of 42 ÷ 9 of 6 - [64 ÷ 48 x 3 – 15 ÷ 8 x (11 – 17) ÷ 9] ÷ 14 is:
3.3 Times 2/27 of 40% of 364=?
What value should come in place of the question mark (?) in the following question?
2000 ÷ 10 + 250 × 2 �...
Simplify the following expressions and choose the correct option.
(3/4 of 528) − (2/3 of 135) = ?
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