Question
'M' invested ₹19,200 at an annual compound interest
rate of 10%, compounded yearly. After 'a' years, the total amount he received was ₹23,232. If 'Q' invested ₹48,000 at an annual compound interest rate of 15%, also compounded yearly for the same duration ('a' years), what would be the total amount received by 'Q'?Solution
We know that, A = P (1 + rate/100)t Or, 23232 = 19200 X (110/100) a Or, (23232/19200) = (11/10) a Or, (121/100) = (11/10) a Or, (11/10) 2 = (11/10) a So, 'a' = 2 Therefore, interest received by 'Q' = 48,000 x (1.15) 2 - 48,000 = 63,480 - 48,000 = Rs. 15,480
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
...
Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
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