Question
Find the probability that a number selected at random
from first hundred number is a multiple of 3 or 5?ÂSolution
Multiple of 3 =99/3=33 Multiple of 5 = 100/5=20 Multiple of both 3 and 5 =90/15=6 So now total number of probable conditions = 33+20-6 =47 Probability = 47/100.
More Probability Questions
The minimum value of 45 sin2 θ + 28 cos2 θ is
Evaluate the following:
sin 60° × cos 30° + sin 30° × cos 60°
If 4sin² θ = 3(1+ cos θ), 0° < θ < 90°, then what is the value of (2tan θ + 4sinθ - secθ)?
- If 2cos²A + 3sin²A = 13/5, then find the value of (sec²A - 1)
- If sin (a + b) = (√3/2) and cos (a – b) = (√3/2), then find sin a.
sin2 17˚ + sin2 19˚ + sin2 21˚ + sin2 23˚ + ……… + sin2 77˚ = ?
If tan² 45°- cos² 60° x sin 45° cos 45° cot 30°, then find the value of 'x'.
If SecA + TanA = 2√2 + 9, then find the value of Sin A + Cos A.
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