A bag contains 4 red bands, 4 green bands and 6 blue bands. Two bands are drawn randomly. What is the probability that at most one band is red?
ATQ, n(B) = 14 C2 n(E) = 4 C2 Probability that both are red = (4 C 2/14 C2)= (6/91) At most one ball is red = [1 - (6/91)] = (91 - 6)/91 = 85/91
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