Question
A bag contains 4 red bands, 4 green bands and 6 blue
bands. Two bands are drawn randomly. What is the probability that at most one band is red?Solution
ATQ, n(B) = 14 C2 n(E) = 4 C2 Probability that both are red = (4 C 2/14 C2)= (6/91) At most one ball is red = [1 - (6/91)] = (91 - 6)/91 = 85/91
?% of (112.31 ÷ 13.97 × 90.011) = 359.98
40.22 of 249.98% + 459.99 ÷ 23.18 = ?
456.9 + 328.10 - 122.98 = ? + 232.11
108.31% of (4.9/9.012) of ? = 23.9% of 2499.9
A man lost one-fourth of his initial amount in the gambling after playing three rounds. The rule of Gambling is that if he wins he will receive Rs. 1000...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
256.12 ÷ 7.92 + 26.11 × 7.82 – 44.09 = ?2