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Total number of eggs in the basket = n(S) = 1200 Let E be the event of selecting a rotten egg from the basket. Number of outcomes favourable to E = n(E) P(E) = n(E)/n(S) 0.22 = n(E)/1200 ⇒ n(E) = 1200 × 0.22 ⇒ n(E) = 264 Therefore, the number of rotten eggs in the basket = 264
(8.083.03 + 59.59% of 839.83) ÷ 16.06 × 24.04 = ?3 + 1012.12
59.978% of 800.315 - 229.95 = ? - 24.95% of 200.15
13.232 + 19.98% of 549.99 = ? × 8.99
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
(44.85% of 799.77 - √143.84)² ÷ (9/11 × 76.77) = ?
25.13% of 39.89% of 74.78% of 60.21% of ? = 44.89
20% of 80 × 26% of 65 = ?
999.99 + 99.99 + 99= ?