Question
Manoj travels from City A to City B. If Manoj drives his
car at 1/5 of his normal speed, then he reaches City B 36 minutes late. Find the time (in minutes) that Manoj would have taken to travel from City A to City B if he drove at his normal speed.Solution
Let Manoj’s normal travel time = t minutes. Here’s the thing: Speed and time are inversely proportional. At normal speed → time = t At 1/5 of normal speed → time becomes 5t He reaches 36 minutes late, so: 5t − t = 36 4t = 36 t = 9 Final Answer Manoj would have taken 9 minutes to travel from City A to City B at his normal speed.
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