Question
If the area of a circle is 616 cm² and a chord XY = 10
cm, then find the perpendicular distance from the center of the circle to the chord XY.Solution
Chord XY =10cm. XP=PY=XY/2 =10/2=5cm. ATQ- Πr2 =616 r2 = 616×7/22 r2 = 28×7 r = 14cm. OX =r =14cm. 
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