Question
O is the centre and the arc PQR subtends an angle of
240° at O. PQ is extended to A. Then ∠AQR is:ÂSolution
ATQ,
Arc PQR at centre = 240° ⇒ Minor arc PR = 360 − 240 = 120° ∠PQR = ½ × 120 = 60° ∠AQR (external, as PQ is extended) = 180 − 60 = 120°
More Previous year papers Questions
(22% of 1500 + 15% of 2200) = ? x 11
√14400 x √8100 - (60)² = ? + (80)²
4368 + 2158 – 596 - ? = 3421 + 1262
[4(1/3) + 4(1/4)] × 24 – 62 = ?2
What value should come in place of the question mark (?) in the following question?
1250 − ( 320 + 180 ) × ...
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
2850 ÷ 2.5 - ? × 42 = 300
(64/25)? × (125/512)?-1 = 5/8
- What will come in place of the question mark (?) in the following questions?
18×4+96÷8=? 3/7 of 504 ÷ 12 + 17 = √?
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