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    Question

    Solve the quadratic equations and determine the relation

    between x and y: Equation 1: 2x² + 8x + 6 = 0 Equation 2: y² - 2y - 8 = 0
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E No relation Correct Answer Incorrect Answer

    Solution

    From equation 1: 2x² + 8x + 6 = 0 Dividing by 2: x² + 4x + 3 = 0 Factorizing: (x + 3)(x + 1) = 0 So, x = -3 or x = -1. From equation 2: y² - 2y - 8 = 0 Factorizing: (y - 4)(y + 2) = 0 So, y = 4 or y = -2. Comparing x and y: • If x = -3 and y = 4, x < y. • If x = -1 and y = 4, x < y. • If x = -3 and y = -2, x < y. • If x = -1 and y = -2, x > y. Thus, no relation Answer: E

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