Question
Solve the quadratic equations and determine the relation
between x and y: Equation 1: 2x² + 8x + 6 = 0 Equation 2: 3y² - 12y + 9 = 0Solution
From equation 1: 2x² + 8x + 6 = 0 Dividing by 2: x² + 4x + 3 = 0 Factorizing: (x + 3)(x + 1) = 0 So, x = -3 or x = -1. From equation 2: 3y² - 12y + 9 = 0 Dividing by 3: y² - 4y + 3 = 0 Factorizing: (y - 3)(y - 1) = 0 So, y = 3 or y = 1. Comparing x and y: • If x = -3 and y = 3, x < y. • If x = -1 and y = 3, x < y. • If x = -3 and y = 1, x < y. • If x = -1 and y = 1, x < y. Thus, x < y. Answer: C
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