Question
A vessel holds 132 liters of milk, and the remaining
liquid is water, which makes up 2/5 of the mixture. If 30 liters of the mixture is removed and x liters of water is added, the ratio of milk to water becomes 6:5. Determine the value of x.Solution
Milk in mixture=132 liters Water in mixture=132*2/3=88 liters (132-30*3/5)/ (88-30*2/5+x) =6/5 114/ (76+x) =6/5 570=456+6x 6x=114 x=19
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